std::chrono::year::operator++, std::chrono::year::operator--
From cppreference.com
constexpr std::chrono::year& operator++() noexcept;
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(1) | (since C++20) |
constexpr std::chrono::year operator++( int ) noexcept;
|
(2) | (since C++20) |
constexpr std::chrono::year& operator--() noexcept;
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(3) | (since C++20) |
constexpr std::chrono::year operator--( int ) noexcept;
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(4) | (since C++20) |
Adds or subtracts 1 from the year value.
1,2) Performs
*this += std::chrono::years{1};.3,4) Performs
*this -= std::chrono::years{1};.Parameters
(none)
Return value
1,3) A reference to this
year after modification.2,4) A copy of the
year made before modification.Notes
If the result would be outside the range [-32767, 32767], the actual stored value is unspecified.
Example
Run this code
#include <chrono>
#include <iostream>
int main()
{
std::cout << std::boolalpha;
std::chrono::year y{2020};
std::cout << (++y == std::chrono::year(2021)) << ' ';
std::cout << (--y == std::chrono::year(2020)) << '\n';
using namespace std::literals::chrono_literals;
y = 32767y;
y++; //← unspecified, see ↑ Notes ↑
std::cout << static_cast<int>(y) << '\n';
}
Possible output:
true true
-32768
See also
adds or subtracts a number of years from a year (public member function) | |
(C++20) |
performs arithmetic on years (function) |